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Ratio of masses of `Na_(3)PO_(4)` and `Ca_(3)(PO_(4))_(2)` each containing 31gm of P is ________A. 0.8B. 0.529C. 1.05D. 0.43

Answer» `n_(p)=n_(Na_(3)PO_(4))xx1 n_(Na_(3)PO_(4))xx2xxn_(Ca_(3))(PO_(4))_(2)`
`n_(p)=n_(Ca_(3))(PO_(4))_(2)xx2 (W_(Na_(3)PO_(4)))/(164)xx2xx(W_(Ca_(3))(PO_(4))_(2))/(310)`
`(W_(Na_(3)PO_(4)))/(W_(Ca_(3))(PO_(4))_(2))=(2xx164)/(310)=(328)/(310)=1.058`


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