Rationalisation of the denominator of 1√5+√2 gives (a)1√10 (b)�

1.	Rationalisation of the denominator of 1√5+√2 gives (a)1√10 (b)√5+√2 (c)√5−√2 (d)√5−√23
Answer» Rationalisation of the denominator of $\frac{1}{\sqrt{5} + \sqrt{2}}$ gives (a) $\frac{1}{\sqrt{10}}$ (b) $\sqrt{5} + \sqrt{2}$ (c) $\sqrt{5} - \sqrt{2}$ (d) $\frac{\sqrt{5} - \sqrt{2}}{3}$

Rationalisation of the denominator of 1√5+√2 gives (a)1√10 (b)√5+√2 (c)√5−√2 (d)√5−√23

Answer»

Rationalisation of the denominator of $\frac{1}{\sqrt{5} + \sqrt{2}}$ gives

(a) $\frac{1}{\sqrt{10}}$ (b) $\sqrt{5} + \sqrt{2}$ (c) $\sqrt{5} - \sqrt{2}$ (d) $\frac{\sqrt{5} - \sqrt{2}}{3}$