Rationalise the denominator of 1/root5+root3

1.	Rationalise the denominator of 1/root5+root3
Answer» 1/√5+√3= 1/√5+√3×√5-√3/√5-√3= √5-√3/(√5)^2-(√3)^2 {(a+b)(a-b)= (a)^2-(b)^2}=√5-√3/5-3=√5-√3/2 ans...Do you satisfied to my given answer???? =1× root 5 - root 3/root 5 + root 3× root 5 - root 3 =Root 5 - root 3/ root 5 square - root 3 square =Root 5 - root 3 / 5 - 3 = Root 5 - root 3/2 Ans.

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