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Reaction, `H_(2)(g)+I_(2)(g)rarr2HI(g)DeltaH=-12.40 kcal`. According to this, the heat of formation of HI will beA. 12.4 kcalB. `-12.4` kcalC. `-6.20` kcalD. 6.20 kcal |
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Answer» Correct Answer - C Heat of formation is for 1 mole. Hence `DeltaH_(f)^(@)(HI)=-12.40//2=-6.20 kcal`. |
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