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| 1. |
Reaction N_(2(g))+ 3H_(2(g)) hArr 2NH_(3(g)) , At 400 K is K_p=41 , So, calculate K_p of following reactions at 400 K. (a)2N_(2(g)) + 6H_(2(g)) hArr 4NH_(3(g)) (b)2NH_(3(g)) hArr N_(2(g))+ 3H_(2(g)) (c)1/2N_(2(g)) + 3/2H_(2(g)) hArr NH_(3(g)) |
| Answer» SOLUTION :(a)`1.67xx10^(-3)`, (B) 0.024 , (C) 6.4 | |