1.

Reaction of diborane with ammonia gives initially

Answer»

`B_(2)H_(6).NH_(3)`
Borazole
`B_(2)H_(6).3NH_(3)`
`[BH_(2)(NH_(3))_(2)]^(+)[BH_(4)]^(-)`

Solution :`3B_(2)H_(6) +6NH_(3) rarr3[BH_(2)(NH_(3))_(2)]^(+)[BH_(4)]^(-) RARR underset("Borazine")(2B_(3)H_(3)H_(6) ) + 12 H_(2)`


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