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Reaction of diborane with ammonia gives initiallyA. `B_(2)H_(6).NH_(3)`B. BorazoleC. `B_(2)H_(6).3NH_(3)`D. `[BH_(2)(NH_(3))_(2)]^(+)[BH_(4)]^(-)` |
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Answer» Correct Answer - D `3B_(2)H_(6) +6NH_(3) rarr 3[BH_(2)(NH_(3))_(2)]^(+)[BH_(4)]^(-) rarr underset("Borazine")(2B_(3)H_(3)H_(6) ) + 12 H_(2)` |
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