Read the passage given below and answer the following questionsPresence of unpaired electrons makes a species paramagnetic. Each unpaired electron has a magnetic moment associated with its spin angular momentum and orbital angular momentum. For the compounds of the first series of transition metals, the contribution of the orbital angular momentum is effectively quenched and hence is considerably important. For these, the magnetic moment is determined by the number of unpaired electrons and is calculated by using the spin-only formula, i.e.,µ = \(\sqrt{n(n+2)}\) Where n = number of unpaired electrons and = magnetic moment (in Bohr magneton, B.M.). If n = 1, then = 1.73 B.M.i. Among the transition metal ion given below, the one with lowest moment is :a). 3d7 b). 3d9 c). 3d2 d). 3d3ii. Which one of the following transition metal ions is paramagnetic? a). Ag2+ b). Zn2+ c). Cu2+ d). Au+iii. The magnetic moment of a transition metal ion is found to be 3.87 B.M. The number of unpaired electrons present in it is: a). 2 b). 3 c). 4 d). 5iv. The value of 'spin only' magnetic moment or one o the following configuration is 2.84 BM. The correct one is: a). d4 (in strong ligand field) b). d4 (in weak ligand field) c). d3 (in weak as well as strong fields) d). d5 (in strong ligand field)