1.

Rearragne the following (I to IV) in the order of increasing masses and choose the correct answer (Atomic masses O=16, Cu=63 and N=4) I. 1 Molecule of oxygen II. 1 atom of nitrogen IIIgt 1xx 10^(-10)g atomic weight of copper

Answer»

II lt I lt III lt IV
IV lt III lt II lt I
II lt III lt I lt IV
III lt IV lt I lt II

Solution :a) I. 1 molecule of `O_(2)` = (32)/(6.022 xx 10^(23)` = 5.3 xx 10^(-23)`G
(ii) 1. atom of N= (14)/(6.022 xx 10^(23)`g = `2.3 xx 10^(-23)`g
IIIgt `10^(-19)` g MOLECULAR weight of oxygen
`= (10^(-10) xx 32 = 3.2 xx 10^(-9)`g
IV. `10^(-10)`gatomic weight of copper `= 10^(-10) xx 63 =6.3 xx 10^(-9)`g
`therefore` ORDER of increasing mass is
II lt I lt III lt IV


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