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RECIhena(ii) 1+4+73 n2T+(37-2) = m3 n-1)4+7+ |
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Answer» n=1(3N-2)=1/2N(3N-1)3(1)-2 = 1/2 (1) (3(1)-1)3-2 = 1/2 (2)1=1 *n=k1+4+7+10...+(3k-2)=1/2k(3k-1) *n=k+11+4+7+10+...+(3k-2)+3(k+1)-2 = 1/2(k+1)(3(k+1)-1)1/2k(3k-1)+3k+3-2=(k+1)(3k+2)/23/2k²-1/2k+3k+1=3k²+5k+2/23k²-k/2 + 3k+1=3k²+5k+2/23k²-k+6k+2/2 = 3k²+5k+2/23k²+5k+2/2 = 3k²+5k+2/2 |
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