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Red colored compound , hemoglobin present in blood contains `0.355% Fe (AM = 56u)` If four atoms of `Fe` are present per molucule of hemoglobin, its molecular mass would beA. `63098 u`B. `78654 u`C. `54786 u`D. `98036 u` |
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Answer» Correct Answer - A As there are 4 atoms of `Fe` per molecule, we have `% Fe = (4 xx AM of Fe)/("MM of hemoglobin") xx 100%` (`AM` is atomic mass, `MM` is molar mass) `0.335% = (4 (56u))/(MM) xx 100%` `:. MM = (4(56u))/(0.335%) xx 100% = 63098 u` |
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