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Reduce the equation `sqrt3y+y+2=0` to (i) slope-intercept form and final the slope and y-intercept. (ii) intercepts form and find the intercepts on the axes. |
Answer» We have `(i)sqrt3x+y+2=0 Rightarrow y=-sqrt3x-2` This is of the form `y=mx+c," where "m=-sqrt3 and c=-2` `therefore y=-sqrt3-2` in the slope-intercept form. Here, slope=`-sqrt3` and y-intercept=-2. (ii) `sqrt3+y+2=0 Rightarrow sqrt3+y=-2` `Rightarrow ((sqrt3)/(-2))x+((1)/(-2))y=1` `Rightarrow (x)/(((-2)/(sqrt3)))+(y)/(-2)=1` This is of the form `(x)/(a)+(y)/(b)=1,` where `a=(-2)/(sqrt3) and b=-2` Thus, `Rightarrow (x)/(((-2)/(sqrt3)))+(y)/(-2)=1` is intercepts form. Here, x-intercept=`(-2)/(sqrt3)` and y-intercept=-2 |
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