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Reduce the following Boolean expression using K-map: F(A, B, C, D) = ∑(3, 4, 5, 6, 7, 13, 15) |
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Answer» There are 2 Pair and 1 Quad that reduce as given below: Pair-1(m3 + m7) reduces to A’CD Pair-2(m4 + m7) reduces to A’BD’ Quad(m1+ m5 + m9 + m13 ) reduces to BD Simplified Boolean expression for given K-map is F(A, B, C, D) = A’CD +’ A’BD’ + BD |
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