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Reduction potential for the following h alf-cell reaction are `Zn rarr Zn rarr Zn^(2+)+2e^(-),E_(Zn^(2+)//Zn)^(@) = -0.76V` `Fe rarr Fe^(2+)+2e^(-),E_(Fe^(2+)//Fe)^(@) = -0.44V` The emf for the cell reaction `Fe^(2+)Zn rarr Zn^(2+)+Fe` will beA. `+0.32V`B. `-0.32V`C. `+1.20V`D. `-1.20V` |
Answer» Correct Answer - A (a) `E_(Zn^(2+)//Zn)^(@)=-0.76V` `E_(Fe^(2+)//Fe)^(@)=-0.44V` Cell reaction, `Fe^(2+)+Zn to Zn^(2+) +Fe` `E_(cell)^(@)=E_("(cathode)")^(@)-E_("(anode)")^(@)` `=-0.44 -(-0.76)` `=+0.32V` |
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