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Refer the diagram; a single-phase supply of 100V, 50Hz is fed to the step-up transformer having primary impedance of 1 ohms and secondary impedance 20 ohms. What is the power consumed by the load of 5 ohms?(a) 20 W(b) 40 W(c) 10 W(d) 100 WI got this question during an online interview.The above asked question is from Machine Ratings topic in division Rating and Loss Dissipation of Electrical Machines

Answer»

The correct OPTION is (a) 20 W

For explanation I WOULD say: The REFERRED resistance to the secondary, Z2=1*(5^2) = 25 ohms

Total resistance at secondary = 25+20 = 45 ohms

Total resistance seen by source = 45+5 = 50 ohms

Hence, CURRENT in secondary = 100/50 = 2 A

Power consumed by the LOAD = I^2 *R = 4*5 = 20 W.



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