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Refers to question 12.i.eZ represents cost , if Z=400x+200y, x+2y ≥ 30, x-y=0 and 5x+2y ≥ 30,What will be the minimum cost? |
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Answer» On solving y ≥ x and 5x+2y=30, we GET `y(30)/(7),x=(30)/(7)` On solving x-y=0 and 2x+y=15, we get x=5, y=5 So, from the shaded FEASIBLE region it is clear that CORRDINATES of corner points are (0,15), (5,5) and `((30)/(7),(30)/(7))` HENCE the minimum cost is 2571.43 |
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