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Repeal above exercise for a proton which is made of two up and one down quark. |
Answer» Solution :For proton two up and ONE down quark `q_(d)= -(1)/(3)e` `q_(u) = +(2)/(3) e` `r=10^(-15)` m `:.` Potential energy of system `U =k[(q_(u)q_(u))/(r)+(q_(u)q_(d))/(r)+(q_(u)d_(d))/(r)]` `=k[((2)/(3)exx(2)/(3)e)/(r)+((2)/(3)exx(-(1)/(3)e))/(r)+((2)/(3)exx(-(1)/(3)e))/(r)]` `=(k)/(r)[(4)/(9)e^(2)-(2)/(9)e^(2)-(2)/(9)e^(2)]` `=(ke^(2))/(9R)[4-2-2]` `=(ke^(2))/(9r)[0]` =0 `:.` Ratio of potential energy of proton to iti mass is zero |
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