Replace A, B by suitable numerals.\(\begin{equation}\frac{\begin{array

1.	Replace A, B by suitable numerals.\(\begin{equation}\frac{\begin{array}[b]{r}6\,\,\,A\\- \,\,\,A\,\,\,B\end{array}}{\,\,\,\,\,3\,\,\,\,\,7}\end{equation}\)
Answer» Here, in tens place, 6 – 3 = 3 Which implies that maximum value of A is 3 Ie. A ≤ 3 Now in units place, A - B = 7 This states that borrowing is involved. ∴ in tens place, 6 – A – 1 = 3 ∴ A = 2 Now in units place, A + 10 – B = 7 …as borrowing is involved ∴ 12 – B = 7 ∴ B = 5

Replace A, B by suitable numerals.\(\begin{equation}\frac{\begin{array}[b]{r}6\,\,\,A\\- \,\,\,A\,\,\,B\end{array}}{\,\,\,\,\,3\,\,\,\,\,7}\end{equation}\)

Answer»

Here, in tens place,

6 – 3 = 3

Which implies that maximum value of A is 3

Ie. A ≤ 3

Now in units place,

A - B = 7

This states that borrowing is involved.

∴ in tens place,

6 – A – 1 = 3

∴ A = 2

Now in units place,

A + 10 – B = 7 …as borrowing is involved

∴ 12 – B = 7

∴ B = 5