Replace A, B, C by suitable numerals.\(\begin{equation} \frac{ \begin{

1.	Replace A, B, C by suitable numerals.\(\begin{equation} \frac{ \begin{array}[b]{r} 4\,\,C\,\,B\,\,6\,\\ +\,\,3\,\,\,6\,\,\,9\,\,A \end{array} }{ 8\,\,\,1\,\,7\,\,3 } \end{equation}\)
Answer» Here, in units place, 6 + A = 3 Ie. A = - 3, which is not possible. Hence A is greater than 10,where, 1 carry is given to tens place. ∴ A + 6 = 13 ∴ A = 7 Now, in tens place, B + 9 + 1 = 7 … as 1 is carried ∴ B = -3, which is not possible. Hence B is greater than 10,where, 1 carry is given to hundreds place. ∴ B + 9 + 1 = 17 ∴ B = 7 Now, in hundreds place, C + 6 + 1 = 1 … as 1 is carried Ie. C = -6, which is not possible. Hence C is greater than 10, where, 1 carry is given to thousands place. ∴ C + 6 + 1 = 11 ∴ C = 4

Replace A, B, C by suitable numerals.\(\begin{equation} \frac{ \begin{array}[b]{r} 4\,\,C\,\,B\,\,6\,\\ +\,\,3\,\,\,6\,\,\,9\,\,A \end{array} }{ 8\,\,\,1\,\,7\,\,3 } \end{equation}\)

Answer»

Here, in units place,

6 + A = 3

Ie. A = - 3, which is not possible.

Hence A is greater than 10,where, 1 carry is given to tens place.

∴ A + 6 = 13

∴ A = 7

Now, in tens place,

B + 9 + 1 = 7 … as 1 is carried

∴ B = -3, which is not possible.

Hence B is greater than 10,where, 1 carry is given to hundreds place.

∴ B + 9 + 1 = 17

∴ B = 7

Now, in hundreds place,

C + 6 + 1 = 1 … as 1 is carried

Ie. C = -6, which is not possible.

Hence C is greater than 10, where, 1 carry is given to thousands place.

∴ C + 6 + 1 = 11

∴ C = 4