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| 1. |
Represent root 3 on number line |
| Answer» Take AB= BC = 1cm{tex}\\angle B = {90^0}{/tex}In {tex}\\triangle{/tex}ABCAC2 = AB2 + BC2AC2 = 1 + 1AC2 = 2AC =\xa0{tex}\\sqrt{2}{/tex}In {tex}\\triangle{/tex}OCD{tex}\\angle C = {90^0}{/tex}\xa0OD2 = OC2 + DC2OD2 = ({tex}\\sqrt{2}{/tex})2 + 1OD2 = 2 + 1OD2 = 3OD =\xa0{tex}\\sqrt{3}{/tex} | |