1.

Represent the turbulent dynamic viscosity in terms of k and ω.(a) ρ ω/k(b) ρ k/ω(c) ρ k^2/ω(d) ρ ω/k^2The question was posed to me in semester exam.Enquiry is from Turbulence Modelling topic in section Turbulence Modelling of Computational Fluid Dynamics

Answer»

Right option is (b) ρ k/ω

The best explanation: The turbulent dynamic VISCOSITY is

μt = ρΘl

Where,

ρ → Density of the flow

ϑ → LENGTH scale of the large eddies

l → Length scale of the small eddies

Replacing with the k and ω equivalents,

\(μ_t=\rho×\SQRT{k}×\frac{\sqrt{k}}{\omega}\)

\(μ_t=\rho×\frac{k}{\omega}\).



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