InterviewSolution
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InterviewSolution
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Resistance of `0.2 M` solution of an electrolyte is `50 ohm`. The specific conductance of the solution is `1.4 S m^(-1)`. The resistance of `0.5 M` solution of the same electrolyte is `280 Omega`. The molar conductivity of `0.5 M` solution of the electrolyte in `S m^(2) mol^(-1)` idA. `5xx10^(2)`B. `5xx10^(-4)`C. `5xx10^(-3)`D. `5xx10^(3)` |
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Answer» Correct Answer - B (b) In first case : `k=(1)/(R )xx(1)/(a)` `(l)/(a)=kxxR=(1.40" ohm"^(-1)m^(-1))xx(50" ohm")` `=70 m^(-1)` In second case : `k=(1)/(R )xx(l)/(a)` `=(1)/((282" ohm"))xx(70 m^(-1))=0.25" ohm"^(-1)m^(-1)` `^^_(m)=(k)/(Mx1000)` `C=0.5 M =(0.5 mol)/(1L)=(0.5 mol)/(m^(3))=0.5 mol m^(-3)` `^^_(m)=((0.25" ohm"^(-1)m^(-1)))/((10^(3)xx0.5 mol m^(-3)))=5xx10^(-4)" ohm"^(-1) m^(2) mol^(-1)` |
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