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Resistance of `0.2 M` solution of an electrolyte is `50 ohm`. The specific conductance of the solution is `1.4 S m^(-1)`. The resistance of `0.5 M` solution of the same electrolyte is `280 Omega`. The molar conductivity of `0.5 M` solution of the electrolyte in `S m^(2) mol^(-1)` idA. `5 xx 10^(3)`B. `5 xx 10^(2)`C. `5 xx 10^(-4)`D. `5 xx 10^(-3)` |
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Answer» Correct Answer - C `K = (1)/(R) xx (l)/(A)` `(K_(1))/(K_(2)) = (R_(2))/(R_(1))` `(1.4)/(K_(2)) = (280)/(50)` `K_(2) = (7)/(28) = (1)/(4) Sm^(-1)` `lambda_(m) =(K)/(M xx 1000) = (1)/(4) xx (1)/(0.5 xx 1000)` `= 5 xx 10^(-4) Sm^(2) mol^(-1)` |
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