1.

Resistance of 0.2M solution of an electrolyte is `50Omega`. The specific conductance of the solution of 0.5M solution of the same electrolyte is `280Omega`. The molar conductivity of 0.5M solution of the electrolyte is S `m^(2)mol^(-1)` isA. `5xx10^(-4)`B. `5xx10^(-3)`C. `5xx10^(3)`D. `5xx10^(2)`

Answer» Correct Answer - A
`x=1.4S//m`
`R=50Omega`
`M=0.2 `
`K=(1)/(R)xx(l)/(A)`
`implies(l)/(A)=1.4xx50m^(-1)`.
Now, new solution has M=0.5, `R=280Omega`
`impliesK=(1)/(R)xx(l)/(A)=(1)/(280)xx1.4xx50=(1)/(4)`
`implies lamda_(M)=(K)/(1000xxM)=((1)/(4))/(1000xx0.5)=(1)/(2000)=5xx10^(-4)`


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