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Resolve each of the following quadratic trinomials into factors:(x - 2y)2 - 5(x - 2y) + 6 |
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Answer» x2 + 4y2 – 4xy – 5x + 10y + 6 Here, coefficient of (x – 2y)2 = 1, coefficient of (x – 2y ) = - 5 and constant = 6 We shall now split up the coefficient of middle term i.e., - 5 into two parts whose sum is -5 and product is 6 (1) = 6 Clearly, - 2 - 3 = - 5 and - 2 (-3) = 6 So, we replace - 5 (x – 3y) = - 2 (x – 2y) – 3 (x – 2y) Thus, we have (x – 2y)2 – 5 (x – 2y) + 6 = (x – 2y)2 – 2 (x – 2y) – 3 (x – 2y) + 6 = (x – 2y - 2) (x - 2y - 3) |
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