Resolve the quadratic trinomials into factors:36a2 + 12abc – 15b2c2

1.	Resolve the quadratic trinomials into factors:36a2 + 12abc – 15b2c2
Answer» We have, 36a² + 12abc – 15b²c² The coefficient of a² is 36 The coefficient of a is 12bc Constant term is -15b²c² So, we express the middle term 12abc as 30abc – 18abc 36a² –12abc– 15b²c² = 36a² + 30abc – 18abc – 15b²c² = 6a (6a + 5bc) – 3bc (6a + 5bc) = (6a + 5bc) (6a – 3bc) = (6a + 5bc) 3(2a – bc)

Answer»

We have,

36a² + 12abc – 15b²c²

The coefficient of a² is 36

The coefficient of a is 12bc

Constant term is -15b²c²

So, we express the middle term 12abc as 30abc – 18abc

36a² –12abc– 15b²c² = 36a² + 30abc – 18abc – 15b²c²

= 6a (6a + 5bc) – 3bc (6a + 5bc)

= (6a + 5bc) (6a – 3bc)

= (6a + 5bc) 3(2a – bc)

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