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Resolving power of a telescope will be more, fi the diameter (a) of the objective isA. independent of the diameter of the objectiveB. lowC. zeroD. high |
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Answer» Correct Answer - D Resolving power of a telescope is given, `x=a/(1.22lamda)!xpropa` where, a = diameter/aperture of objective a telescope and `lamda`= wavelength of light. when the aperture (diameter) of objective is large, then its resolving power is high. |
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