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Result of mohls half leaf experiment lab activity |
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Answer» sed to show that photosynthesis cannot take place in the absence of carbon dioxide, which combines with H+ IONS in the light-independent PHASE of photosynthesis(Calvin's cycle) to form glucose in the PRESENCE of enzymes.The part of the leaf exposed to KOH or soda lime(CA(OH)2 + NaOH) is not able to conduct photosynthesis due to the absence of carbon dioxide, which is absorbed by the KOH, so it tests negative for starch, iodine SOLUTION remains reddish brown when poured over that part of the leaf.The part of the leaf that was out of the flask is able to conduct photosynthesis as carbon dioxide is available, so it tests positive for starch, the leaf turns blue black when iodine solution is poured over it. |
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