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Rhombus show that diagonal AC bisects angle A as well as angle C and diagonal BD bisects Angle B as well as angle d |
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Answer» [In RHOMBUS all SIDE are EQUAL and diagonols
⇒AB=BC=CD=DA ⇒AC⊥BD In ΔABC ⇒AB=BC ⇒∴∠CAB=∠ACB ⇒AO=OC ∴∠ABO=∠CBO and simillarly in ΔADC ⇒AD=DC ⇒AO=OC ∴corresponding ANGLE are equal ⇒∠DAC=∠DCA and∠CDO=∠ADO Hence, ACbisect ∠A and ∠C and BDbisects ∠Band∠D |
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