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Rms value of the saw-tooth voltage of peak value `V_(0)` as shown in- A. `(V_(0))/(2)`B. `(V_(0))/(sqrt(2))`C. `(V_(0))/(3)`D. `(V_(0))/(sqrt(3))` |
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Answer» Correct Answer - D `V(t) = -V_(0) + (2V_(0))/(T) xx t` `V_(rms)= sqrt((overset(T)underset(0)int V^(2)dt)/(overset(T)underset(0)intdt)) = sqrt((overset(T)underset(0)int(V_(0)^(2)+(4V_(0)^(2)t^(2))/(T^(2))-(4V_(0)^(2)T)/(T))dt)/(overset(T)underset(0)intdt)` `sqrt(((V_(0)^(2)T+(4V_(0)^(2)T)/(3)-2V_(0)^(2)T))/(T) = (V_(0))/(sqrt(3))` |
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