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Rod `AB` of length `1m` is released from the shown position. End `A` undergoes perfect inelastic collision with ground `C` is mid-point of rod. Angular velocity of rod just after collision is `(3x)/2rad//sec`. Find `x`. (Assuming no slipping on ground) |
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Answer» Correct Answer - 5 Conserving angular momentum about point of impact. `msqrt(2gh).L/2sintheta=(mL^(2))/3omega` `impliesomega=3/2sin30^(@).(sqrt(2xxgH))/L=15/2rad//sec` |
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