Rohit was 4 times as old as his son 8 yearsago. after years, Rohit wil

1.	Rohit was 4 times as old as his son 8 yearsago. after years, Rohit will be twice as old ashis son. What are their present ages?
Answer» Let present age of Rohit=x years Let his sons present age=y years Therefore atq x-8=4[y-8] x-8=4y-32 x-4y=-32+8 x-4y=-24………….(1) Now 8 years hence their ages will be x+8=2[y+8] x+8=2y+16 x-2y=16–8 x-2y=8……………(2) Subtract (2) from (1) x-4y=-24 _x-2y = _8 -2y=-32 y=16 Substitute value of y in eq (1) x-4y=-24 x-4×16=-24 x-64 =-24 x=-24+64=40 .: x=40 Hence Rohits present age =40 years and his son's present age=16 years

Rohit was 4 times as old as his son 8 yearsago. after years, Rohit will be twice as old ashis son. What are their present ages?

Answer»

Let present age of Rohit=x years

Let his sons present age=y years

Therefore atq

x-8=4[y-8]

x-8=4y-32

x-4y=-32+8

x-4y=-24………….(1)

Now 8 years hence their ages will be

x+8=2[y+8]

x+8=2y+16

x-2y=16–8

x-2y=8……………(2)

Subtract (2) from (1)

x-4y=-24

_x-2y = _8

-2y=-32

y=16

Substitute value of y in eq (1)

x-4y=-24

x-4×16=-24

x-64 =-24

x=-24+64=40

.: x=40

Hence Rohits present age =40 years

and his son's present age=16 years