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S^(2-) and SO_(3)^(2-) ions can be distinguished by using |
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Answer» `(CH_(3)COO)_(2) Pb` `Pb(CH_(3)COO)_(2)` gives a BLACK ppt with `S^(2-)` ions (e.g., `H_(2)S`) while no precipitate is formed with `SO_(3)^(2-)` ions. `Pb(CH_(3)COO)_(2) + H_(2)S rarr PBS rarr + underset(("Black ppt"))(2CH_(3) COOH)` `Na_(2) [Fe(CN)_(5)NO]` gives a purple colouration with `S^(2-)` ions `(Na_(2)S)` while no precipitate is formed with `SO_(3)^(2-)` ions. `Na_(2) [Fe(CN)_(5) NO] + Na_(2)S rarr Na_(4) [Fe(CN)_(5)NOS]` |
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