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s ug that there is no slack in the string.6. 1.5 m tall boy is standing at some distance from a 30 m tall building. The angelevation from his eyes tohis eyes to the top of the building increases from 30° to 60° as he walkstowards the building. Find the distance he walked towards the building.7. From a noint on |
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Answer» A| | | 30 mt | B----------C 60°----D 30° |1.5 m EAE=height of building (30m)BE= 1.5m boy height in ∆ABCTAN60=AB/BC√3= 28.5/BC√3BC=30BC= 30/√3= 30√3/√3√3=10√3 IN ∆ABD TAN30=AB/BD1/√3= 30/BDBD= 30√3 CD= BD - BC = 30√3 - 10√3 = 20√3 MT = 20×1.732 = 34.64MTHe moves 34.64mt towards building |
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