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साबित कीजिए की `A nn (B-C) =(A nn B)-(A nn C)` |
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Answer» माना की `x in A nn (B-C)` `implies x in A` और `x in (B-C)` `implies x in A` और `(x in B` और `x notin C)` `implies (x in A` और `x in B)` और `(x in A` और `x notin C)` `implies x in (A nn B)` और `x notin (A nn C)` `implies x in (A nn B)-(A nn C)` अतः `A nn (B-C) sube (A sube B)-(A nn C)` ...(1) अब, माना की `y in (A nn B)-(A nn C)` `implies y in (A nn B)` और `y notin (A nn C)` `implies (y in A` और `y in B)` और `(y in A` और `y notin C)" "[ :. y notin A nn C implies y notin C" as "y in A]` `implies y in A` और `(y in B` और `y notin C)` `implies y in A` और `y in (B-C)` `implies y in A nn (B-C)` `:. (A nn B)-(A nn C) sube A nn (B-C)` ...(2) `:.` (1) और (2) से, `A nn (B-C)=(A nn B)-(A nn C)` |
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