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Sagar bought 30 tickets in.all, of which some cost 15 and the-rest. cost 20.the total cost of the tickets was 54how many tickets of 20 were boughtow man |
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Answer» Let the no. of 15 rs tickets be x and 20rs ticket be y hencex+y=30....(1) case 2 15x+20y=540 .....(2) dividing whole equation by 3 we get 3x+4y=108 by elimination method x+y=30.. X3 3x+4y=108-3x-3y=-90hence y=18 x= 30-18 , x=12 y=18 |
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