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Salt cake `(Na_(2)SO_(4))` is prepared as follows: `2NaCl + H_(2) SO_(4) rarr Na_(2)SO_(4) + 2HCl` How much salt cake could be produced from `100.0 g` of 90% pure saltin the above reaction?A. `109.8 g`B. `54.9 g`C. `36.6 g`D. `209.8 g` |
Answer» Correct Answer - A Weight of `Na_(2)SO_(4) = (100 g NaCl)` `((90.0 g NaCl)/(100 g "mixture"))((1 "mol" NaCl)/(58.5 g NaCl))` `((1 "mol" Na_(2)SO_(4))/(2 "mol"NaCl))((142 g NaSO_(4))/("mol"Na_(2)SO_(4)))` `= (100 xx 90 xx 1 x 1 x 142)/(100 xx 58.5 xx 2)` `= 109.79 ~~ 109.8 g` |
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