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Sample Question Paper II, 200813. From a pair of linear equations in two variables using the following information andsolve it graphically:Five years ago, Sagar was twice as old as Tiru. Ten year later Sagar's age will be ten yearsmore than Tiru's age. Find their present ages. What was the age of Sagar wheborn?wasSample Question Paper II 2008 |
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Answer» It is given that, Five years ago sagar was twice as old as tiru. Ten years later sagar age will be ten year more than tiru age Let x be the age of tiru five years ago. Then the age of sager 5 years ago = 2x Present age of tiru = x + 5 Present age of sagar = 2x + 5 After 10 years, age of tiru = (x + 5 )+ 10 = x + 15 age of sagar = (2x + 5)+10 = 2x + 15 To find x Ten years later sagar age will be ten year more than tiru age we can write, (x + 15) + 10 = 2x + 15 x + 25 = 2x + 15 x = 10 To find present age of tiru and sagar Present age of tiru = x + 5 = 10 + 5 = 15 Present age of sagar = 2x + 5 = 2*10 + 5 = 25 To find the age of sagar when tiru was born Present age of tiru = 15 Present age of sagar = 25 The age of sagar when tiru was born = Present age of sagar - present age of tiru = 25 - 15 = 10 years Therefore the age of sagar when tiru was born = 10 years |
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