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Sand drops from a stationary hopper at the rat of 5 kgs^(-1) onto a conveyor belt moving with a constant speed of 2 ms^(-1). What is the force required to keep the belt moving and what is the power delivered by the motor moving the belt ?

Answer» <html><body><p></p>Solution :Impulse J = Ft = mv, `F=(mv)/(t)`<br/>`v=2 ms^(-1), (m)/(t)=5 kgs^(-1) <a href="https://interviewquestions.tuteehub.com/tag/rarr-1175461" style="font-weight:bold;" target="_blank" title="Click to know more about RARR">RARR</a> F=10 <a href="https://interviewquestions.tuteehub.com/tag/n-568463" style="font-weight:bold;" target="_blank" title="Click to know more about N">N</a>`<br/><a href="https://interviewquestions.tuteehub.com/tag/powe-2945861" style="font-weight:bold;" target="_blank" title="Click to know more about POWE">POWE</a> `P=(W)/(t)=(Fs)/(t)=<a href="https://interviewquestions.tuteehub.com/tag/fv-458643" style="font-weight:bold;" target="_blank" title="Click to know more about FV">FV</a> = 10xx2=20` <a href="https://interviewquestions.tuteehub.com/tag/watt-1450279" style="font-weight:bold;" target="_blank" title="Click to know more about WATT">WATT</a>.</body></html>


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