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Sand drops from a stationary hopper at the rat of 5 kgs^(-1) onto a conveyor belt moving with a constant speed of 2 ms^(-1). What is the force required to keep the belt moving and what is the power delivered by the motor moving the belt ? |
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Answer» Solution :Impulse J = Ft = mv, `F=(mv)/(t)` `v=2 ms^(-1), (m)/(t)=5 kgs^(-1) RARR F=10 N` POWE `P=(W)/(t)=(Fs)/(t)=FV = 10xx2=20` WATT. |
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