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Sand drops from a stationary hopper at the rate of 5 kgs^(-1) onto a conveyor belt moving with a constant speed of 2ms^(-1). What is the force required to keep the belt moving and what is the power delivered by the motor moving the belt ? |
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Answer» Solution :IMPULSE j = FT = mv, `F = (mv)/(t)` `v=2ms^(-1),(m)/(t)=5KGS^(-1)rArrF=10N` power `P=(W)/(t)=(Fs)/(t)=Fv` `=10xx2=20` walt. |
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