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Sate Gay Lussac's Law. Calculate the pressure exerted by 4 mole of agas occuping a volume of 1.5m^(3) at 100 K. Given R=8.314 J/k/mol. |
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Answer» Solution :GAY Lussac.s law (PRESSURE-temperature relationship) Gay Lussac.s law states that at constant volume, pressure of a fixed amount of a GAS varies DIRECTLY with the temperature. Given `n=4` moles `V=1.5m^(3),T=100klR=8.314`J/kmol, `P=?` `P=nRTimplies(nRT)/V=(4"moles"xx8.314"Jk mol"xx100k)/(1.5m^(3))=8269Pa` |
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