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Sate Gay Lussac's Law. Calculate the pressure exerted by 4 mole of agas occuping a volume of 1.5m^(3) at 100 K. Given R=8.314 J/k/mol.

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Solution :GAY Lussac.s law (PRESSURE-temperature relationship)
Gay Lussac.s law states that at constant volume, pressure of a fixed amount of a GAS varies DIRECTLY with the temperature.
Given `n=4` moles
`V=1.5m^(3),T=100klR=8.314`J/kmol, `P=?`
`P=nRTimplies(nRT)/V=(4"moles"xx8.314"Jk mol"xx100k)/(1.5m^(3))=8269Pa`


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