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सदिश `2hati + 3hatj` तथा Y-अक्ष के बीच कोण है :A. `tan^(-1)(3//2)`B. `tan^(-1)(2//3)`C. `sin^(-1)(2//3)`D. `cos^(-1)(2//3)` |
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Answer» Correct Answer - B माना `vecA = 2hati + 3hatj` व `vecB = hatj` (Y-अक्ष) तथा इनके बीच कोण `theta` है | तब `cso theta = (vecA * vecB)/(AB) = ((2)(0) + (3)(1))/(sqrt((13))(1)) = (3)/(sqrt(13))` अथवा `tan theta = (2)/(3).` |
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