InterviewSolution
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InterviewSolution
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`sec^(2)theta==(4ab)/((a+b)^(2)),` where a, b `inR` is true if and olny ifA. `a+b ne0`B. `a=b, a ne0`C. `a=b`D. `a ne 0, bne0` |
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Answer» Correct Answer - B We known that `sec ^(2)thetage1` `therefore sec^(2)theta=(4ab)/((a+b)^(2))` `impliesa,b ne0and-(4ab)/((a+b)^(2))ge1` `impliesa,b ne0and (4ab)/((a+b)^(2))-1ge0` `impliesa,b ne0and-((a-b)^(2))/((a+b)^(2))ge0` `impliesa,b ne0and -(a-b)^(2)ge0` `impliesa, b ne0and (a-b)^(2)le0impliesa =b and a ne0` |
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