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\sec ^{6} x-\tan ^{6} x=1+3 \sec ^{2} x \times \tan ^{2} x |
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Answer» a³-b³=(a-b)³+3ab(a-b)1+tan²x=sec²x(sec²x)³-(tan²x)³=(sec²x-tan²x)³+3sec²xtan²x(sec²x-tan²x) =1³+3sec²xtan2x(1) =1+3tan²xsex²xhence proved |
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