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\sec \theta+\tan \alpha=P then findcoseco |
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Answer» cosec theta = 1/sin thetaP = tanФ + secФp -secФ = tanФp² + sec²Ф - 2 p secФ = tan²Ф= sec²Ф - 1So secФ = (p² + 1) / 2p so cosФ = 2p/(1+p²)sinФ = √[1 - cos²Ф ] = (p²-1)/(1+p²)cosec theta= 1/(p²-1)/(1+p²)= (p^2+1)/(p^2-1) |
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