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Second law of motion derives 3rd law |
| Answer» Acc. to 3rd lawFab=―FbaAcc to 2nd law Fab=dpA/dt....1SimilarlyFab=dpB/dt...2Adding 1 and 2Fab+Fba=(dpA/dt+dpB/dt)=d(pa+pb)/dtAcc to conservation od momentumpA +pB=constantSo Fab=―FbaHence proved | |