Seema’s age is twice of Radha’s age. Radha’s age is 40 years. Fi

1.	Seema’s age is twice of Radha’s age. Radha’s age is 40 years. Find their average age?1. 402. 453. 604. 30
Answer» Correct Answer - Option 3 : 60 Given: Radha’s age = 40 years Seema’s age = 2 × Radha’s age Concept: Average age = Total age / Total persons Solution: Radha’s age = 40 years Seema’s age = 2 × Radha’s age Seema’s age = 2 × 40 ⇒ 80 years Average = Total age / Total persons = (40 + 80) / 2 = 120/2 = 60 ∴ Their average age is 60.

Seema’s age is twice of Radha’s age. Radha’s age is 40 years. Find their average age?1. 402. 453. 604. 30

Answer» Correct Answer - Option 3 : 60

Given:

Radha’s age = 40 years

Seema’s age = 2 × Radha’s age

Concept:

Average age = Total age / Total persons

Solution:

Radha’s age = 40 years

Seema’s age = 2 × Radha’s age

Seema’s age = 2 × 40 ⇒ 80 years

Average = Total age / Total persons

= (40 + 80) / 2

= 120/2

= 60

∴ Their average age is 60.

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Seema’s age is twice of Radha’s age. Radha’s age is 40 years. Find their average age?1. 402. 453. 604. 30

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