Sekhar gives a quarter of his sweets to Renu and then gives 5 sweets t

1.	Sekhar gives a quarter of his sweets to Renu and then gives 5 sweets to Raji. He has 7 sweets left. How many did he have to start with?
Answer» Number of sweets with Sekhar = x say. Number of sweets given to Renu = 1/4 × x = x/4 Number of sweets given to Raji = 5 Till he has 7 sweets left. x – ( x/4 + 5) = 7 ⇒ x – x/4 – 5 = 7 ⇒ x – x/4 = 7 + 5 = 12 ⇒ \(\frac{4x\,-\,x}{4}\) = 12 ⇒ 3x/4 = 12 ⇒ x = 12 × 4/3 = 16 ∴ x = 4 × 4 = 16 ∴ Number of sweets with Sekhar at the beginning = 16

Sekhar gives a quarter of his sweets to Renu and then gives 5 sweets to Raji. He has 7 sweets left. How many did he have to start with?

Answer»

Number of sweets with Sekhar = x say.

Number of sweets given to Renu = 1/4 × x = x/4

Number of sweets given to Raji = 5

Till he has 7 sweets left.

x – ( x/4 + 5) = 7

⇒ x – x/4 – 5 = 7

⇒ x – x/4 = 7 + 5 = 12

⇒ \(\frac{4x\,-\,x}{4}\) = 12

⇒ 3x/4 = 12

⇒ x = 12 × 4/3 = 16

∴ x = 4 × 4 = 16

∴ Number of sweets with Sekhar at the beginning = 16