

InterviewSolution
Saved Bookmarks
1. |
Select odd man out(incorrect) from the following expressions for kinetic energy in pure rolling. |
Answer» <html><body><p>In pure <a href="https://interviewquestions.tuteehub.com/tag/rolling-1190754" style="font-weight:bold;" target="_blank" title="Click to know more about ROLLING">ROLLING</a> K.E. `=(K.E.)_("<a href="https://interviewquestions.tuteehub.com/tag/trans-1425477" style="font-weight:bold;" target="_blank" title="Click to know more about TRANS">TRANS</a>")+(K.E.)_("Rot")`<br/>In pure rolling K.E. `=1/2 mv_(CM)^(2)+1/2I_(CM)omega^(2)`<br/>In pure rolling `K.E. =1/2mv^(2)` <br/>In pure rolling kinetic energy with reference to centre of mass is K.E. `=1/2mv_(CM)^(2)(1+K^(2)//<a href="https://interviewquestions.tuteehub.com/tag/r-611811" style="font-weight:bold;" target="_blank" title="Click to know more about R">R</a>^(2))`</p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :It is an incorrect expression. It is not for pure rolling.</body></html> | |