1.

Select odd man out(incorrect) from the following expressions for kinetic energy in pure rolling.

Answer»

In pure ROLLING K.E. `=(K.E.)_("TRANS")+(K.E.)_("Rot")`
In pure rolling K.E. `=1/2 mv_(CM)^(2)+1/2I_(CM)omega^(2)`
In pure rolling `K.E. =1/2mv^(2)`
In pure rolling kinetic energy with reference to centre of mass is K.E. `=1/2mv_(CM)^(2)(1+K^(2)//R^(2))`

SOLUTION :It is an incorrect expression. It is not for pure rolling.


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