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Select the all four quantum number of last `e^(-)` of lanthenum (z = 57) atomA. `4,3,0,+(1)/(2)`B. `6,1,-1,+(1)/(2)`C. `5,2,0,+(1)/(2)`D. `7,1,0,+(1)/(2)` |
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Answer» Correct Answer - C Electron configuration of La (57) is [Xe] `6s^(2) 5d^(1) 4f 5d 6p` Last `e^(-)` enters in 5d orbital. `therefore` Quantum numbers are `5,2,0,+(1)/(2)` |
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